Integrand size = 29, antiderivative size = 102 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {3 x}{4 a^2}-\frac {2 \cos (c+d x)}{a^2 d}+\frac {\cos ^3(c+d x)}{a^2 d}-\frac {\cos ^5(c+d x)}{5 a^2 d}+\frac {3 \cos (c+d x) \sin (c+d x)}{4 a^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{2 a^2 d} \]
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Time = 0.16 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {2948, 2836, 2713, 2715, 8} \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {\cos ^5(c+d x)}{5 a^2 d}+\frac {\cos ^3(c+d x)}{a^2 d}-\frac {2 \cos (c+d x)}{a^2 d}+\frac {\sin ^3(c+d x) \cos (c+d x)}{2 a^2 d}+\frac {3 \sin (c+d x) \cos (c+d x)}{4 a^2 d}-\frac {3 x}{4 a^2} \]
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Rule 8
Rule 2713
Rule 2715
Rule 2836
Rule 2948
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sin ^3(c+d x) (a-a \sin (c+d x))^2 \, dx}{a^4} \\ & = \frac {\int \left (a^2 \sin ^3(c+d x)-2 a^2 \sin ^4(c+d x)+a^2 \sin ^5(c+d x)\right ) \, dx}{a^4} \\ & = \frac {\int \sin ^3(c+d x) \, dx}{a^2}+\frac {\int \sin ^5(c+d x) \, dx}{a^2}-\frac {2 \int \sin ^4(c+d x) \, dx}{a^2} \\ & = \frac {\cos (c+d x) \sin ^3(c+d x)}{2 a^2 d}-\frac {3 \int \sin ^2(c+d x) \, dx}{2 a^2}-\frac {\text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{a^2 d}-\frac {\text {Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,\cos (c+d x)\right )}{a^2 d} \\ & = -\frac {2 \cos (c+d x)}{a^2 d}+\frac {\cos ^3(c+d x)}{a^2 d}-\frac {\cos ^5(c+d x)}{5 a^2 d}+\frac {3 \cos (c+d x) \sin (c+d x)}{4 a^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{2 a^2 d}-\frac {3 \int 1 \, dx}{4 a^2} \\ & = -\frac {3 x}{4 a^2}-\frac {2 \cos (c+d x)}{a^2 d}+\frac {\cos ^3(c+d x)}{a^2 d}-\frac {\cos ^5(c+d x)}{5 a^2 d}+\frac {3 \cos (c+d x) \sin (c+d x)}{4 a^2 d}+\frac {\cos (c+d x) \sin ^3(c+d x)}{2 a^2 d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(308\) vs. \(2(102)=204\).
Time = 1.03 (sec) , antiderivative size = 308, normalized size of antiderivative = 3.02 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {5 (1+24 d x) \cos \left (\frac {c}{2}\right )+110 \cos \left (\frac {c}{2}+d x\right )+110 \cos \left (\frac {3 c}{2}+d x\right )-40 \cos \left (\frac {3 c}{2}+2 d x\right )+40 \cos \left (\frac {5 c}{2}+2 d x\right )-15 \cos \left (\frac {5 c}{2}+3 d x\right )-15 \cos \left (\frac {7 c}{2}+3 d x\right )+5 \cos \left (\frac {7 c}{2}+4 d x\right )-5 \cos \left (\frac {9 c}{2}+4 d x\right )+\cos \left (\frac {9 c}{2}+5 d x\right )+\cos \left (\frac {11 c}{2}+5 d x\right )-5 \sin \left (\frac {c}{2}\right )+120 d x \sin \left (\frac {c}{2}\right )-110 \sin \left (\frac {c}{2}+d x\right )+110 \sin \left (\frac {3 c}{2}+d x\right )-40 \sin \left (\frac {3 c}{2}+2 d x\right )-40 \sin \left (\frac {5 c}{2}+2 d x\right )+15 \sin \left (\frac {5 c}{2}+3 d x\right )-15 \sin \left (\frac {7 c}{2}+3 d x\right )+5 \sin \left (\frac {7 c}{2}+4 d x\right )+5 \sin \left (\frac {9 c}{2}+4 d x\right )-\sin \left (\frac {9 c}{2}+5 d x\right )+\sin \left (\frac {11 c}{2}+5 d x\right )}{160 a^2 d \left (\cos \left (\frac {c}{2}\right )+\sin \left (\frac {c}{2}\right )\right )} \]
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Time = 0.37 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.66
method | result | size |
parallelrisch | \(\frac {-60 d x -\cos \left (5 d x +5 c \right )-5 \sin \left (4 d x +4 c \right )+40 \sin \left (2 d x +2 c \right )+15 \cos \left (3 d x +3 c \right )-110 \cos \left (d x +c \right )-96}{80 d \,a^{2}}\) | \(67\) |
risch | \(-\frac {3 x}{4 a^{2}}-\frac {11 \cos \left (d x +c \right )}{8 a^{2} d}-\frac {\cos \left (5 d x +5 c \right )}{80 d \,a^{2}}-\frac {\sin \left (4 d x +4 c \right )}{16 d \,a^{2}}+\frac {3 \cos \left (3 d x +3 c \right )}{16 d \,a^{2}}+\frac {\sin \left (2 d x +2 c \right )}{2 d \,a^{2}}\) | \(90\) |
derivativedivides | \(\frac {\frac {16 \left (-\frac {3 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}-\frac {7 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}-\frac {\left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}-\frac {5 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}+\frac {7 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}-\frac {3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}+\frac {3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{32}-\frac {3}{20}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{5}}-\frac {3 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}}{d \,a^{2}}\) | \(129\) |
default | \(\frac {\frac {16 \left (-\frac {3 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}-\frac {7 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}-\frac {\left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}-\frac {5 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}+\frac {7 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}-\frac {3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}+\frac {3 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{32}-\frac {3}{20}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{5}}-\frac {3 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}}{d \,a^{2}}\) | \(129\) |
norman | \(\frac {-\frac {105 x \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {33 x \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {189 x \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {15 x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {147 x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {63 x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {105 x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}-\frac {105 x \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}-\frac {189 x \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {147 x \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {12}{5 a d}-\frac {105 x \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {63 x \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {3 x}{4 a}-\frac {193 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {39 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {33 x \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {15 x \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 a}-\frac {9 x \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 a}-\frac {71 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {57 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{10 d a}-\frac {3 x \left (\tan ^{17}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 a}-\frac {9 \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {1679 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d a}-\frac {9 x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 a}-\frac {311 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {383 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d a}-\frac {361 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {221 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {1387 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d a}-\frac {653 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{10 d a}-\frac {29 \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {269 \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {115 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}-\frac {3 \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{7} a \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}\) | \(637\) |
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Time = 0.28 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.67 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {4 \, \cos \left (d x + c\right )^{5} - 20 \, \cos \left (d x + c\right )^{3} + 15 \, d x + 5 \, {\left (2 \, \cos \left (d x + c\right )^{3} - 5 \, \cos \left (d x + c\right )\right )} \sin \left (d x + c\right ) + 40 \, \cos \left (d x + c\right )}{20 \, a^{2} d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1608 vs. \(2 (94) = 188\).
Time = 33.93 (sec) , antiderivative size = 1608, normalized size of antiderivative = 15.76 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=\text {Too large to display} \]
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Leaf count of result is larger than twice the leaf count of optimal. 290 vs. \(2 (94) = 188\).
Time = 0.31 (sec) , antiderivative size = 290, normalized size of antiderivative = 2.84 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {\frac {\frac {15 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {120 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {70 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {200 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {40 \, \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} - \frac {70 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} - \frac {15 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}} - 24}{a^{2} + \frac {5 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {10 \, a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {10 \, a^{2} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {5 \, a^{2} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}} + \frac {a^{2} \sin \left (d x + c\right )^{10}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{10}}} - \frac {15 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{2}}}{10 \, d} \]
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Time = 0.43 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.25 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=-\frac {\frac {15 \, {\left (d x + c\right )}}{a^{2}} + \frac {2 \, {\left (15 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 70 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 40 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 200 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 70 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 15 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 24\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{5} a^{2}}}{20 \, d} \]
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Time = 10.36 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.87 \[ \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^2} \, dx=\frac {3\,\cos \left (3\,c+3\,d\,x\right )}{16\,a^2\,d}-\frac {11\,\cos \left (c+d\,x\right )}{8\,a^2\,d}-\frac {3\,x}{4\,a^2}-\frac {\cos \left (5\,c+5\,d\,x\right )}{80\,a^2\,d}+\frac {\sin \left (2\,c+2\,d\,x\right )}{2\,a^2\,d}-\frac {\sin \left (4\,c+4\,d\,x\right )}{16\,a^2\,d} \]
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